Write , so the covariance operator isFor ,so is self-adjoint. Moreover,so it is a positive operator.
Let be any orthonormal basis. Tonelli theorem and Parseval identity giveA positive operator with finite trace is a trace-class operator, completing the proof.
For every orthonormal basis of the infinite-dimensional Hilbert space , the identity operator satisfiesPart a shows that every covariance operator of a square-integrable Hilbert-space random element is trace-class. Therefore the identity cannot be a covariance operator.
Choose a unit vector and define the rank-one operatorIt is bounded, self-adjoint, and Hilbert-Schmidt, with . Butso it is not positive. Since every covariance operator is positive, is the required counterexample.
Since and the eigenfunctions can be chosen orthonormally, independence of the sample givesThis remains valid for repeated eigenvalues after choosing an orthonormal eigenbasis within each eigenspace.
Articles by others on the same topic
There are currently no matching articles.