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Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 344 / 3 / c / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 344 3 c
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Detailed balance says that each equilibrium transition is balanced by its time reverse:
Peq​(1)PF​(1→2)=Peq​(2)PB​(2→1).
(1)
With the Boltzmann distribution Peq​∝e−βH and ΔH=H2​−H1​, this requires
PB​PF​​=e−βΔH.
(2)
Parts a and b instead give exp[−(2ζ/σ2)ΔH]. Equality for every pair of endpoints yields the fluctuation-dissipation relation for a Langevin particle
σ2=β2ζ​=2ζkB​T.​
(3)

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