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Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 356 / 1 / d / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 356 1 d
2026-09-28  0 By others on same topic  0 Discussions Create my own version
The only independent current is
J(t)=αP1​−βP2​=re−(α+β)t.
(1)
Hence the total transient entropy production is
S˙tot​=J(t)logβP2​(t)αP1​(t)​≥0.​
(2)
Its relaxational part may be written
S˙rel​=JlogP2​P1ss​P1​P2ss​​,(P1ss​,P2ss​)=α+β1​(β,α),
(3)
while the steady or housekeeping entropy production is zero. Both the current and total production vanish as t→∞.

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