Let be the transition rate from to and define the probability current . The master equation is . Differentiating the Shannon entropy and symmetrizing gives
Adding the entropy flow to the environment produces the nonnegative entropy production rate of a Markov chain
The paper's displayed is the negative of the thermodynamic system entropy, so its derivative has the opposite sign before the environmental contribution is added.
For the two-state chain,
with .
Eliminating gives . Therefore
With ,
The only independent current is
Hence the total transient entropy production is
Its relaxational part may be written
while the steady or housekeeping entropy production is zero. Both the current and total production vanish as .
At stationarity,
Thus every edge current vanishes and the two-state system satisfies detailed balance. A network containing only one undirected edge cannot sustain a stationary cycle current.
With indices understood cyclically,
The circulant generator has eigenvalues and , where and . Expanding the initial vector in its three Fourier eigenvectors gives
For the oriented edge , . Substitution in the Markov-chain entropy production gives
Since ,
The second term is relaxational and vanishes for the uniform stationary distribution. The steady entropy exported to the environment is therefore
At stationarity , but the cycle current is . Therefore the chain is out of detailed balance exactly when
The nonzero cycle affinity sustains the stationary current and positive housekeeping entropy production.

Articles by others on the same topic (0)

There are currently no matching articles.