The competing exponential clocks calculation gives
so is exponential with rate . Also
The exponential memoryless property gives
After the first of two equal-rate clocks rings, the residual lifetime of the other clock is, by memorylessness, a fresh exponential variable of rate , independent of the first ringing time and of which clock rang. Hence
and these variables are independent.
Take the spatial Fourier transform of the wave equation. The transformed initial-value problem is
and hence
Part (c) and the convolution theorem turn the first term into
For the second term, choose with . Part (b) says , so
Part (c) now makes its inverse transform
Combining the two terms gives the D'Alembert formula
Let and . Part (c) makes and independent identically distributed exponential variables of rate . The change of variables has Jacobian , and integrating over gives density one for . Therefore the uniform ratio of independent exponential variables gives

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