The exponential memoryless property gives
After the first of two equal-rate clocks rings, the residual lifetime of the other clock is, by memorylessness, a fresh exponential variable of rate , independent of the first ringing time and of which clock rang. Henceand these variables are independent.
Take the spatial Fourier transform of the wave equation. The transformed initial-value problem isand hence
Part (c) and the convolution theorem turn the first term intoFor the second term, choose with . Part (b) says , soPart (c) now makes its inverse transformCombining the two terms gives the D'Alembert formula
Let and . Part (c) makes and independent identically distributed exponential variables of rate . The change of variables has Jacobian , and integrating over gives density one for . Therefore the uniform ratio of independent exponential variables gives
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