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Past exam of the mathematics course of the University of Cambridge / 2023 / ii / Paper 1 / 31J / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 1 31J b
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
A function f:C→R is strictly convex when, for distinct x,y∈C and 0<t<1,
f(tx+(1−t)y)<tf(x)+(1−t)f(y)​.
(1)
Suppose distinct points x and y were both minimizers, with minimum value m. Since C is a convex set, their midpoint belongs to C, while strict convexity gives
f(2x+y​)<2f(x)+f(y)​=m,
(2)
a contradiction. Thus any minimizer is unique, which is the uniqueness of a minimizer of a strictly convex function.

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