The degenerate subspace has ordered basisUsing the ladder actions,Thus degenerate perturbation theory asks us to diagonalizeIts normalized eigenvectors and first-order energies areThere is no order- admixture from other unperturbed levels.
In fact, preserves , so this two-dimensional eigenspace of is invariant. Directly,Thereforefor every real , with no omitted higher-order terms. This is exact diagonalization within a degenerate subspace, specifically the resonant two-to-one oscillator coupling.
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