The degenerate subspace has ordered basis
Using the ladder actions,
Thus degenerate perturbation theory asks us to diagonalize
Its normalized eigenvectors and first-order energies are
There is no order- admixture from other unperturbed levels.
In fact, preserves , so this two-dimensional eigenspace of is invariant. Directly,
Therefore
for every real , with no omitted higher-order terms. This is exact diagonalization within a degenerate subspace, specifically the resonant two-to-one oscillator coupling.

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