Differentiate the eigenvalue equation
at , where . Suppressing the argument gives
Left-multiplication by the transpose of the unit left eigenvector and use of cancel the terms involving :
Because the eigenvalue is simple, , and hence the first-order perturbation of a simple eigenvalue is
The definition of the operator norm, followed by the Cauchy-Schwarz inequality, gives
Therefore

Articles by others on the same topic (0)

There are currently no matching articles.