In local coordinates, for
the exterior derivative is
Applying again gives symmetric second partial derivatives contracted with the antisymmetric wedge , hence . Expanding coefficients and moving past a degree- form gives the graded Leibniz rule
For a function and smooth , the chain rule gives
Every differential form is locally a sum of products . Since pullback preserves products and wedge products, the function case and the graded Leibniz rule imply
for every form.
The de Rham cohomology of is
Because pullback commutes with , it sends closed forms to closed forms and exact forms to exact forms. Thus a smooth map induces
Let be a smooth homotopy and write . If , Cartan's magic formula gives
Integrating defines a degree-minus-one operator satisfying
For closed , the difference is exact, so smoothly homotopic maps induce the same map on de Rham cohomology.
If is a homotopy equivalence with inverse up to homotopy , functoriality and homotopy invariance give
Hence is an isomorphism.
We induct on . The claim is immediate for . In the stated cover, is contractible. The homotopy
deformation retracts onto the hyperplane , which is . Moreover,
deformation retracts onto .
The Mayer--Vietoris sequence for the de Rham complex contains
For odd , the group on the right vanishes by contractibility and the induction hypothesis, while the group on the left vanishes because is positive and even and is neither nor . Thus the middle group vanishes. For , the preceding map
is surjective because all three spaces are connected, so the connecting map into is zero. Therefore all odd de Rham cohomology groups of vanish.

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