PutFor every nonzero integer ,LetThese are disjoint nonempty subsets of . If , thenso . Similarly, if , thenso .
The ping-pong lemma now identifies the subgroup generated by and withBoth generators have infinite order, so this is a free group of rank two inside the special linear group .
Use the injective group homomorphism from part (a). If , its image is an integral matrix . Choose a prime number that does not divide one nonzero entry of . The reduction modulo a prime in an integral matrix group homomorphismthen sends to a nonidentity element. Its target is a finite group, so the composite map separates from the identity. Hence is a residually finite group.
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