OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 102 / 5 / a / ii

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 102 5 a
2026-09-24  0 By others on same topic  0 Discussions Create my own version
  • Table of contents
    • Solution ii

Solution

 0  0
ii
For sl2​, the Verma module has basis
v,,fv,,f2v,…
(1)
by the Poincare-Birkhoff-Witt theorem. If hv=λv, then
efrv=r(λ−r+1)fr−1v.
(2)
For λ=−d with d>0, the coefficient is
r(−d−r+1)=0
(3)
for every r≥1. Thus no frv with r>0 is a singular vector.
Any nonzero submodule contains a weight vector frv because the h-weights are distinct. Applying er gives a nonzero multiple of v, after which applying powers of f generates all of M(−d). Hence
M(−d) is irreducible and infinite-dimensional.​
(4)
This is also the negative-highest-weight case of Reducibility of an sl2 Verma module.

 Ancestors (11)

  1. a
  2. 5
  3. Paper 102
  4. iii
  5. 2024
  6. Past exam of the mathematics course of the University of Cambridge
  7. Mathematics course of the University of Cambridge
  8. Course of the University of Cambridge
  9. University of Cambridge
  10. List of universities
  11.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook