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Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 341 / 5 / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 341 5 a
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Write H=−∂x2​+V(x). The real potential and periodic boundary conditions make H a self-adjoint operator. Since ut​=−iHu,
dtd​∫−11​∣u∣2dx=2Re∫−11​u,ut​dx=2Re(−i∫−11​u,Hudx)=0,
(1)
because the expectation of a self-adjoint operator is real. Equivalently, integrating the kinetic term by parts leaves ∫∣ux​∣2dx and the periodic boundary term cancels. Thus the continuous Schrodinger equation preserves its L2 norm.

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