The source-free Maxwell equations in a linear medium are
with and .
Take complex plane waves
The divergence equations give
and Faraday's law gives
Ampère's law gives
Substituting the expression for and using
yields
Hence the plane electromagnetic wave in a linear medium has
and equivalently
Let be the unit normal pointing from the minus medium to the plus medium. Integrating the Maxwell equations across an infinitesimal pillbox or loop gives the dielectric-interface boundary conditions
and
Thus tangential and are continuous, as are normal and .
Because , the normal electric field generally jumps according to
The tangential displacement field generally jumps because . Since the permeability is common, continuity of tangential is continuity of tangential ; together with normal- continuity, every component of is continuous. The same common also makes the normal component of continuous.
Choose the interface as and write the incident, reflected, and transmitted fields as plane waves with wavevectors . The boundary conditions must hold for every tangential coordinate and every time. The phase matching at a planar wave interface therefore requires
and equality of tangential wavevectors:
The incident and reflected waves are in the same medium, so
. Equality of their tangential components gives
hence
At fixed frequency, is proportional to the refractive index . Tangential phase matching between incident and transmitted waves gives the Snell law for electromagnetic waves:
or
Here if the vacuum speed is used to normalize the index.
Take the plane of incidence to be the -plane, so all three electric polarizations point along . Write their signed scalar amplitudes as . Tangential- continuity gives
For each plane wave,
Continuity of its tangential component gives
where the common proportionality between and cancels. Solving the two equations gives the transverse-electric Fresnel reflection coefficient
Using Snell's law to eliminate ,
Since and is common, . Therefore
The numerator is consequently strictly negative throughout
, and
Thus transverse-electric polarization has no Brewster angle in this setting.

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