Take complex plane wavesThe divergence equations giveand Faraday's law givesAmpère's law givesSubstituting the expression for and using
yieldsHence the plane electromagnetic wave in a linear medium hasand equivalently
yieldsHence the plane electromagnetic wave in a linear medium hasand equivalently
Let be the unit normal pointing from the minus medium to the plus medium. Integrating the Maxwell equations across an infinitesimal pillbox or loop gives the dielectric-interface boundary conditionsandThus tangential and are continuous, as are normal and .
Because , the normal electric field generally jumps according toThe tangential displacement field generally jumps because . Since the permeability is common, continuity of tangential is continuity of tangential ; together with normal- continuity, every component of is continuous. The same common also makes the normal component of continuous.
Choose the interface as and write the incident, reflected, and transmitted fields as plane waves with wavevectors . The boundary conditions must hold for every tangential coordinate and every time. The phase matching at a planar wave interface therefore requiresand equality of tangential wavevectors:
The incident and reflected waves are in the same medium, so
. Equality of their tangential components giveshence
. Equality of their tangential components giveshence
At fixed frequency, is proportional to the refractive index . Tangential phase matching between incident and transmitted waves gives the Snell law for electromagnetic waves:orHere if the vacuum speed is used to normalize the index.
Take the plane of incidence to be the -plane, so all three electric polarizations point along . Write their signed scalar amplitudes as . Tangential- continuity givesFor each plane wave,Continuity of its tangential component giveswhere the common proportionality between and cancels. Solving the two equations gives the transverse-electric Fresnel reflection coefficientUsing Snell's law to eliminate ,Since and is common, . ThereforeThe numerator is consequently strictly negative throughout
, andThus transverse-electric polarization has no Brewster angle in this setting.
, andThus transverse-electric polarization has no Brewster angle in this setting.
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