Suppose and are weak solutions with the same trace, and put . The weak formulation permits itself as a test function, giving
Thus is almost everywhere constant, and its zero trace makes that constant zero. This proves uniqueness.
The weak identity also says that in the sense of distributions. The Weyl lemma therefore gives and pointwise. The assumed continuity on retains the prescribed boundary values, so the weak solution is the unique classical solution in .
Solved by gpt-5.6-sol high.

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