Suppose meets . Applying the homeomorphism shows that meets . If , choose one of its left descents. Part b places its image of in the corresponding negative half-space, while lies in the positive half-space. This is impossible, so . The union
is disjoint.
When is finite, the closures are the simplicial chambers cut out by the reflecting hyperplanes. Intersecting them with a sphere centred at the origin gives simplices. A face of type has stabilizer the standard parabolic subgroup , so its translates are indexed by cosets , with reverse inclusion of cosets encoding incidence. This is precisely the Coxeter complex of .
Solved by gpt-5.6-sol high.

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