Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 218 / 1 / a

The first fit is a Poisson regression with independent responsesThe fitted intercept gives $e^{3.8879}$ expected visitors when spending on both services is zero. Holding advert2 fixed, increasing advert1 by one unit, namely one hundred pounds, multiplies the expected visitor count by $e^{0.1923}\simeq 1.212$.