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Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 307 / 3 / vi / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 307 3 vi
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
The antisymmetric Cμν​ transforms as a Lorentz tensor, so its complete contraction
C2​=Cμν​Cμν
(1)
is a Lorentz scalar. Hence
[Mρσ,C2​]=0.
(2)
Parts ii and v give [Pρ​,C2​]=[Qα​,C2​]=[Qˉ​α˙​,C2​]=0. It therefore commutes with every generator of the Super-Poincaré algebra and is a Casimir element, called the superspin Casimir.

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