Past exam of the mathematics course of the University of Cambridge / 2026 / ii / Paper 3 / 11G / b

Table of contents
- Solution b

Solution

Apply the formula to the complete quotient and use the determinant identity to express

b_{n}

. Eliminating the complete quotient from the consecutive expressions yields the stated quadratic for

q_{n + 1} / q_{n}

. Taking the compatible signs for adjacent indices and using

c_{n} \leq b_{j}

gives

2 c_{n} a_{n + 1} \leq 2 b_{n} a_{n + 1} \leq 1 - 4 b_{n} b_{n + 1} + 1 - 4 b_{n - 1} b_{n} \leq 2 1 - 4 c_{n}^{2} .

 Ancestors (10)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version