The Trace form of a Lie algebra representation is invariant becauseChoose a basis orthonormal for the positive-definite form of the compact simple algebra. Any invariant bilinear form determines an endomorphism commuting with the irreducible adjoint action; Schur lemma makes it scalar. Thus . Since is anti-Hermitian,The inequality is strict because the kernel of the nontrivial irreducible representation is an ideal and hence zero. Therefore with .
Articles by others on the same topic
There are currently no matching articles.