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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2013 / Paper 2 / 13 / c / ii / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2013 Paper 2 13 c ii
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The integral converges absolutely: near zero it behaves like logx, and at infinity like (logx)/x2. Let its value be J. The integration by substitution x=1/t gives
J=∫0∞​1+t2−logt​dt=−J.
(1)
Therefore
J=0​.
(2)
Absolute convergence makes this cancellation between the two ends legitimate.

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