Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2015 / Paper 2 / 15 / a / ii / Solution

Use the same general solution. The first two conditions now give $A+B=3$ and $-2A-6B+12=-2$, so $A=1$, $B=2$. HenceAt $t=\log \sqrt{2}$, its value is $1/2-3/4+2/8=0$, so the third condition is also satisfied. This is the unique consistent solution.