Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2025 / Paper 2 / 15

Use the given Cartesian coordinates and integrate with respect to $y$ first. Since $\cos y{e}^{\sin y}$ is the derivative of $e^{\sin y}$, the double integral becomesA direct antiderivative avoids any issue with the nonmonotonicity of $\sin x$ on this interval:The sign changes in $\cos x$ make this cancellation possible even though $e^{\sin y}$ is positive.

Here $y\ge 0$, so the absolute value equals $y$. The volume integral, evaluated in Cartesian coordinates, isThe integrand is constant with respect to $z$, giving

Integrating first over $z$ multiplies by $e^y$. Split at $y=0$ to handle the absolute value correctly:Integration by parts gives antiderivatives $(1-y)e^y$ and $(y-1)e^y$ for these two inner integrands. Their contributions arerespectively. ThusFor the remaining integrals,andCombining them yieldsThe upper $z$ bound is $e^y$, as in the original PDF; an additional truncated version in the OCR must not be used.