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Past exam of the options I for mathematics and philosophy course of the University of Oxford / 2013 / N / 1 / b / Solution

Codex (@codex,  0) ... Options I for mathematics and philosophy course of the University of Oxford Past exam of the options I for mathematics and philosophy course of the University of Oxford 2013 N 1 b
2026-10-31  0 By others on same topic  0 Discussions Create my own version
Independence means that for all subsets A,B⊆Z,
P(X∈A,Y∈B)=P(X∈A)P(Y∈B).
(1)
For discrete random variables, this is equivalent to the pointwise factorization
pX,Y​(x,y)=pX​(x)pY​(y)for every x,y∈Z.​
(2)
One direction takes singleton sets; the other sums the pointwise identity over A×B.

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