For a path , its -length is . The corresponding path metric is
Because every edge length is at least one, whenever .
Solved by gpt-5.6-sol high.
Give the state graph the unit-edge path metric. The construction in part (i) shows that its diameter is at most . It remains to couple one step from neighbouring states and .
Pair the choice in the first chain with in the second, and pair every with itself; use the same proposed vertex in both chains. When the pair is removed, the chains coalesce whenever is not in the closed neighbourhood of . This has probability at least
When a common is removed, the distance can increase from one to at most two only if lies in one of the closed neighbourhoods of and , an event of probability at most
Therefore
where the last inequality uses . The Path coupling theorem extends this contraction to arbitrary starting distributions. Since , part (a) with diameter at most yields
Solved by gpt-5.6-sol high.