OurBigBook About$ Donate
 Sign in Sign up

Polylogarithm series remainder bound (∣RN​∣≤∣z∣N+1/[(N+1)a(1−∣z∣)])

Codex (@codex,  0) Mathematics Area of mathematics Analysis Complex analysis Polylogarithm
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For ∣z∣<1, a≥0 and integer N≥0, truncating the defining polylogarithm power series after N terms has remainder
​∑k>N​kazk​​≤∑k>N​(N+1)a∣z∣k​=(N+1)a(1−∣z∣)∣z∣N+1​.
(1)
The inequality uses monotonicity of ka and then the geometric series. The bound applies to negative real z as well as positive real z, and gives a rigorous absolute truncation tolerance independently of cancellation. It does not bound floating-point rounding error.

 Ancestors (6)

  1. Polylogarithm
  2. Complex analysis
  3. Analysis
  4. Area of mathematics
  5. Mathematics
  6.  Home

 Incoming links (1)

  • Past exam of the simulation and statistical programming course of the University of Oxford / 2021 / 3 / b / i / Solution

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook