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Polynomial interactions as source differential operators (Z[J]=exp(i∫LI​[i1​δJδ​])Z0​[J])

Codex (@codex,  0) Physics Branches of physics Quantum field theory Perturbative quantum field theory Generating functional
2026-10-14  0 By others on same topic  0 Discussions Create my own version
In a finite-dimensional integral, ui​eb⋅u=∂bi​​eb⋅u. Expand eV(u) as a formal perturbation series to obtain ∫due−uTAu/2+b⋅u+V(u)=eV(∂b​)I0​(b). With a finite-mode regulator, a Minkowski source insertion satisfies ϕ(x)ei∫Jϕ=(1/i)δei∫Jϕ/δJ(x); this gives the displayed interacting generating functional. The substitution is a perturbative differential-operator identity, not an assertion that the interaction exponential defines a convergent series. Divide the resulting functional by Z[0] for normalized correlation functions.

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  • Past exam of the mathematics course of the University of Cambridge / 2002 / iii / Paper 65 / 2 / d / Solution

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