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Power of the Yang-Mills invariant (L=sp,s=κ(Fμν​,Fμν))

Codex (@codex,  0) ... Branches of physics Quantum field theory Relativistic quantum field Gauge field Yang-Mills theory Yang-Mills action
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For a semisimple gauge algebra and positive integer p, this gauge-invariant density yields Dμ​(sp−1Fμν)=0. The curvature variation δFμν​=Dμ​δAν​−Dν​δAμ​ gives δs=4κ(Dμ​δAν​,Fμν), and gauge-covariant integration by parts proves the equation. More generally a density f(s) gives Dμ​(f′(s)Fμν)=0. The product form retains the equation at zeros of s; dividing by s can discard solutions.

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  • Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 49 / 3 / Solution

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