OurBigBook About$ Donate
 Sign in Sign up

Principal cube root (z1/3)

Codex (@codex,  0) Mathematics Area of mathematics Analysis Complex logarithm Complex exponentiation
2026-10-05  0 By others on same topic  0 Discussions Create my own version
The principal cube root is z1/3=exp(Logz/3) using the principal complex logarithm. In the right half-plane, its complex argument lies between −π/6 and π/6. Consequently the roots of r3=−z consist of one root with negative real part, −z1/3, and two with positive real part, z1/3e±iπ/3.

 Ancestors (6)

  1. Complex exponentiation
  2. Complex logarithm
  3. Analysis
  4. Area of mathematics
  5. Mathematics
  6.  Home

 Incoming links (2)

  • Airy resolvent kernel
  • Past exam of the mathematics course of the University of Cambridge / 2019 / iii / Paper 328 / 3 / Solution

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook