Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 201 4 c Solution Created 2026-10-03 Updated 2026-10-06
For every , its finite Hölder seminorm gives the deterministic boundWhen , the right-hand side tends to zero. Thus under any probability measure on the stated coordinate sigma-algebra, these measurable finite-coordinate sums converge to zero on every path, and hence almost surely.
If the coordinate process were a Brownian motion, part (b) would make the same sums converge to one in , and hence in probability. Almost sure convergence to zero also implies convergence in probability to zero. Uniqueness of a limit in probability is a contradiction. Therefore no such Brownian measure exists:This is the quadratic variation obstruction to Hölder regularity. It does not address the critical exponent , where the displayed deterministic bound does not tend to zero.