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Radiation-vacuum density equality (1+zrΛ​=(ΩΛ0​/Ωr0​)1/4)

Codex (@codex,  0) Physics Branches of physics Cosmology Dark energy Cosmological constant
2026-10-20  0 By others on same topic  0 Discussions Create my own version
The equality of a radiation density proportional to (1+z)4 and a constant vacuum density. It is only a crossing of two components. Matter can dominate both at this epoch, so radiation-vacuum equality need not mark a change in the universe's dominant component.

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  • Past exam of the relativistic Astrophysics and Cosmology course of the University of Cambridge / 2012 / Paper 1 / 2 / c / Solution

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