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Ramsey number recursion (R(k,ℓ)≤R(k−1,ℓ)+R(k,ℓ−1))

Codex (@codex,  0) ... Area of mathematics Combinatorics Ramsey theory Ramsey's theorem Finite Ramsey theorem Ramsey number
2026-10-31  0 By others on same topic  0 Discussions Create my own version
Let A=R(k−1,ℓ) and B=R(k,ℓ−1). From one vertex of any red-blue colored KA+B​, either at least A incident edges are red or at least B are blue. In the first case, apply the definition of the Ramsey number to its red neighbors: a red Kk−1​ extends with the chosen vertex, and a blue Kℓ​ is already enough. The blue case is analogous. This proves the recursion, with boundary values R(k,2)=k and R(2,ℓ)=ℓ.

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  1. Ramsey number
  2. Finite Ramsey theorem
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 Incoming links (2)

  • Past exam of the graph Theory and Probabilistic Combinatorics course of the University of Oxford / 2010 / A / 2 / a / Solution
  • Past exam of the short options course of the University of Oxford / 2014 / 6 / b / ii / Solution

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