Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 102 5 a ii Solution Created 2026-09-24 Updated 2026-10-14
For , the Verma module has basisby the Poincaré-Birkhoff-Witt theorem. If , thenFor with , the coefficient isfor every . Thus no with is a singular vector.
Any nonzero submodule contains a weight vector because the -weights are distinct. Applying gives a nonzero multiple of , after which applying powers of generates all of . HenceThis is also the negative-highest-weight case of Reducibility of an sl2 Verma module.
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 102 2 iii Solution Created 2026-09-24 Updated 2026-10-14
For the sl2 Lie algebra, let be the highest-weight vector. The Poincaré-Birkhoff-Witt theorem gives the basis , and the defining Lie brackets implyA positive-degree basis vector is singular exactly when is a positive integer. Therefore is irreducible when .
If , the vector has weight and generates a submodule isomorphic to . The latter is irreducible because . Every nonzero submodule contains a singular vector by the preceding part, and the displayed coefficient shows that this is the only possible proper singular vector. Henceis the unique proper nonzero submodule, as summarized by the Reducibility of an sl2 Verma module.