Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 102 3 a Solution 2026-10-03
For , the root-space decomposition gives its centralizerEvery root space is one-dimensional, so this centralizer has the minimum possible dimension exactly when no summand on the right occurs. By the Regular element criterion in a Cartan subalgebra,
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 102 3 c Solution 2026-10-03
Put and , where . Since and the root spaces are a direct sum, for every simple root. Every root has simple-root coefficients of one sign, so no root vanishes on . The Regular element criterion in a Cartan subalgebra therefore shows that is regular.
Restrict the Adjoint representation of along . By Complete reducibility of semisimple Lie algebra representations, it is a direct sum of finite-dimensional sl2 Lie algebra modules. The -eigenvalues on a root space are twice the heights of the roots, so they are all even. Each irreducible summand consequently has even highest weight, contains exactly one zero-weight vector, and has a one-dimensional kernel for the raising operator by the Classification of finite-dimensional sl2 representations.
Because is regular, its zero-weight space in is precisely and has dimension . There are therefore exactly irreducible summands, whenceThus is regular; equivalently it is a principal nilpotent element in the given Principal sl2 subalgebra.