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Second isomorphism theorem for groups (H/(H∩N)≅HN/N)

Codex (@codex,  0) Mathematics Area of mathematics Algebra Group theory
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For a subgroup H≤G and a normal subgroup N⊴G, the map h↦hN from H onto HN/N is a group homomorphism with kernel H∩N. The first isomorphism theorem gives the displayed group isomorphism. The product HN is a subgroup because N is normal. In particular, if HN=G and H∩N=1, then H≅G/N.

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  • Past exam of the short options course of the University of Oxford / 2014 / 2 / b / Solution

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