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Assign the seventh individual's event weights $(1/3,1/3,1/3)$, the conditional probabilities obtained from the original Kaplan–Meier estimator. The last three fractional counts areTheir conditional event fractions are $1/3$, $1/2$, and $1$, exactly as in the original censored-data calculation. Hence the fractional allocation reproduces the original estimate:This illustrates self-consistency of Kaplan–Meier estimation: distributing the unobserved event according to the current conditional fitted event distribution leaves the fitted distribution unchanged. The first imputation in part (b) was not such a self-consistent allocation.