A useful finite conjunction of closure assertions requires empty set, pairing, set union, set difference, Cartesian products, all finite tuple domains , and the following operations on their relations: relative complements, intersections, coordinate projections and pullbacks along finite coordinate maps, together with equality and membership restricted to . The arities and maps are quantified objects, so these requirements form finitely many first-order formulas, not an infinite schema. In a transitive set, individual finite tuples exist by pairing and union, making the tuple-domain assertions correct externally. Atomic truth relations, Boolean operations and projection then compute the truth table of each coded first-order formula correctly by finite induction. Thus satisfaction for a set structure and the relation are absolute for shared arguments. Every nonzero limit level of the relative constructible hierarchy is closed under these operations, since each result can be defined at finitely many subsequent stages.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 121 2 iii Solution Created 2026-10-03 Updated 2026-10-05
Use relative constructible level recognition. The finite coding conditions matter here: merely writing “every set is relatively constructible” inside an arbitrary transitive set does not ensure that its computations are correct.
Let be a single finite conjunction expressing finite relation closure for set-theoretic coding. Concretely require the empty set, pairing, set union, set difference, Cartesian products, and the following uniform relation operations: for each finite ordinal and each set , the set of finite tuples exists; relations on these tuple domains can be complemented, intersected, projected along a coordinate and pulled back along finite coordinate maps; the equality and membership relations restricted to exist. These are finitely many first-order closure assertions with quantified, not an axiom schema. Each operation is specified by its usual elementwise membership equivalence. Transitivity makes the operations correct externally. Finite tuple domains are also correct: every individual finite tuple is already present by pairing and union.
These conditions make satisfaction for a set structure absolute. For a fixed coded first-order formula, compute its truth relations on by induction: equality and membership give the atomic cases, relative complement gives negation, intersection gives logical conjunction, and projection gives existential quantification. All required truth tables exist by and agree with the actual ones. Thus the first-order assertion is absolute whenever belong to a transitive structure satisfying : require that each member of has such a finite formula-and-parameter definition, and that each coded definition contributes a member of . Codes are finite objects; no truth predicate for the ambient universe is being used.
Write for the coded relative constructible stage assertion: is an ordinal and there is a function with domain , with , , at nonzero limit ordinals, and . Under , any such internal code is correct by transfinite induction. Restrictions of a code to shorter domains exist by the relation operations. Define the one-free-variable first-order formulaAll displayed abbreviations expand into first-order formulas of the membership language.
Suppose is transitive, , and . Let be the externally defined set of indices of stage codes in . It contains , is downward closed by restricting codes, and has no largest member by the last conjunct. Thus is a nonzero limit ordinal . Correctness of stage codes gives for , hence by transitivity. Conversely the exhaustion conjunct puts every in some such level. Therefore
For the converse, every with nonzero limit satisfies : each listed operation on parameters from one level is definable at finitely many later levels, still below . Moreover stage histories appear below every limit constructible level. Here is the essential limit step of that lemma. If the histories for are available in , the correct predicate defines their graph of endpoints as a subset of . No endpoint with can belong to , because would then give , contradicting Axiom of foundation. The defined graph therefore has domain exactly . Adjoining its final pair takes finitely many more stages. Together with finite successor extensions, this proves by transfinite induction that every belongs to for some finite .