Six-point amplitudes in phi-fourth theory ($2\to 4$)

For a connected six-external-leg Feynman diagram made from quartic vertices, $4V=6+2I$ and $L=I-V+1$ give $V=L+2$, $I=2L+1$. A tree therefore has two vertices and one internal line; partitioning six labelled external legs into two triples gives ten tree channels. A one-loop triangle has three vertices, three internal lines and two external legs at each vertex. With external labels fixed, that triangle has symmetry factor one. Other one-loop topologies also contribute to the full amplitude.