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Slow circular inspiral under tangential drag (r˙=−(1+q)Vc​rD​,q=dlogVc​/dlogr)

Codex (@codex,  0) ... Physics Branches of physics Astrophysics Galaxy Galaxy dynamics Chandrasekhar dynamical friction
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For a slowly evolving circular orbit with tangential deceleration D>0, the specific angular momentum is j=rVc​(r) and its torque is j˙​=−rD. Differentiating j gives the displayed drift when 1+q=0. The positive local decay time r/(2∣r˙∣) is (1+q)Vc​/(2D). In a uniform-density core q=1, so it is Vc​/D; for a flat galaxy rotation curve q=0, it is Vc​/(2D). Simply setting V˙c​=−D neglects the radial contribution to angular momentum change.

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  • Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 72 / 2 / c / Solution

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