Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 105 3 b ii Solution Created 2026-10-03 Updated 2026-10-05
The assertion about all is false as printed in the original PDF. Take , , and . This is a nonzero smooth Dirichlet function, but and . In particularAlready at , is not defined on its stipulated domain, because . Extending to for this example would give zero, not an inner product. Additional boundary conditions are essential.
The corrected spaces are the Sobolev domains of powers of an elliptic Dirichlet operator. Let be the Dirichlet realization of an elliptic operator, and setIn particular , , and also requires . The formulas in the question define inner products on these spaces.
Here is the norm-equivalence proof on the corrected domains. The base cases are the inner product at and part (i) at . Standard Dirichlet elliptic regularity, together with invertibility from the Lax-Milgram theorem, gives for every integer The first estimate applies when ; invertibility absorbs the usual lower-order term. Moreover, is an isomorphism. To see surjectivity, solve with zero Dirichlet trace for ; regularity gives , and for each further required trace. The formulas satisfyInduction therefore givesInjectivity of each iterate of gives positive definiteness. These spaces are ; the spectral characterization of elliptic Dirichlet domains in the next part makes the half-powers precise. On the paper's uncorrected spaces the claim is valid at , but fails in general beyond them.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 105 3 c Solution Created 2026-10-03 Updated 2026-10-05
Take , the natural initial-data assumption needed for the requested convergence but not explicitly stated in this subpart. Use the genuine Dirichlet eigensystem from part (b)(iii) and put . The spectral construction of a parabolic solution isEach finite sum has zero Dirichlet boundary condition and satisfies .
To justify all derivatives, fix . For any integers , the squared norm of a tail of the th time derivative isuniformly for . Use the corrected Sobolev domains of powers of an elliptic Dirichlet operator, not the inaccurate unqualified assertion in the PDF. Their norm equivalence gives convergence in every ordinary . The Sobolev embedding theorem then gives convergence of every desired spatial derivative by choosing large enough. Thus termwise differentiation is justified, , and for every . The trace remains zero, and holds pointwise.
Finally Parseval identity givesby the dominated convergence theorem, since each factor tends to zero and is bounded by one. No boundary compatibility of the initial data is required for positive-time smoothness.
Let be the orthonormal basis of Dirichlet eigenfunctions for a strictly positive Dirichlet realization of an elliptic operator, with eigenvalues . ThenFor integers , these domains are the Sobolev domains of powers of an elliptic Dirichlet operator. At the condition is just Parseval identity and imposes no boundary condition. At it describes and , respectively. Higher impose traces of powers of , not only the trace of . For on , the smooth Dirichlet function has sine coefficients proportional to for odd , so the weighted sum diverges at despite its ordinary regularity.
For a time-independent strictly positive Dirichlet realization of an elliptic operator and , the eigenfunction expansionsolves with homogeneous Dirichlet boundary conditions. For , every power times the exponential is bounded, so the series and all its time derivatives converge in all the Sobolev domains of powers of an elliptic Dirichlet operator. Elliptic regularity and the Sobolev embedding theorem give smoothness up to the spatial boundary for positive time. Parseval identity and the dominated convergence theorem give in as .