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Steady circular Couette profile (Ω=A+B/r2)

Codex (@codex,  0) ... Physics Branches of physics Fluid mechanics Viscous fluid flow Couette flow Taylor-Couette flow
2026-10-18  0 By others on same topic  0 Discussions Create my own version
For a homogeneous Newtonian fluid with constant kinematic viscosity, a steady axisymmetric purely azimuthal flow obeys vϕ′′​+vϕ′​/r−vϕ​/r2=0. Writing vϕ​=rΩ gives (r3Ω′)′=0, so Ω=A+B/r2. A domain containing the rotation axis requires B=0 for regularity; rotating walls in an annulus can sustain B=0. An arbitrary time-dependent profile instead evolves by ∂t​Ω=ν(Ω′′+3Ω′/r) within this ansatz.

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  1. Taylor-Couette flow
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  • Past exam of the astrophysical fluid dynamics course of the University of Cambridge / 2021 / Section B / 6 / b / Solution
  • Taylor-Couette flow

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