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Write $B=\beta$ for the driving Brownian motion throughout; the two symbols in the displayed formulas refer to the same process. For $t<1$ the deterministic integrand is square-integrable on $[0,t]$, sois well defined. The Itô product rule, with zero quadratic covariation against the deterministic factor, givesFor the other form, apply the same Itô product rule to $B_t/(1-t)$:Multiplying by $1-t$ gives the stochastic integral representation of a Brownian bridgeThe drift coefficient is singular only at the terminal endpoint, so this calculation is performed on compact subintervals of $[0,1)$.

The Brownian bridge covariance kernel is invariant under reversing both times, and its mean is zero. The two centered Gaussian processes therefore have equal finite-dimensional laws. Equality on countably many rational coordinates transfers the event of continuity at zero to the reversed endpoint. Interior continuity then extends the rational-time limit to all times. This proves the terminal continuity of the stochastic integral representation of a Brownian bridge.