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sulfide first opens one epoxide by backside attack, giving a carbon-bound thiolate and an alkoxide. Using the same numbering, take this first attack at C2: the C2–S bond is down and C3–O remains up.

The attached sulfur still bears a nucleophilic lone pair and negative charge. It attacks C5 of the second epoxide intramolecularly, breaking C5–O and closing a bridge between C2 and C5. Work-up protonates the oxygen anions at C3 and C6. Thus B is 7-thiabicyclo$[\mathrm{2.2.1}]$heptane-2,5-diol, with both OH groups on the face opposite the sulfur bridge.

Both C–S bonds are formed by inversion at their attacked epoxide carbons. Because the original epoxides are cis, both new C–S bonds point to the same opposite face and one sulfur chemical atom can connect them. The 1,4 bridge gives two five-membered sulfur-containing circuits, unlike the more strained closure between nearby 1,3 positions.

The sulfur therefore replaces two separate external nucleophiles: two epoxides are opened but only one sulfur chemical atom is incorporated. Adding that sulfur and two work-up protons gives ${\mathrm{C}}_6{\mathrm{H}}_{10}{\mathrm{O}}_2\mathrm{S}$, consistent with B.

In the ionic assignment, both tetrahedral anions would require Mn(VII), $d^0$. Such a high oxidation state is strongly oxidizing and is best supported by strong bonding to oxygen. Short Mn–O bonds combine good orbital overlap with oxygen's resistance to further oxidation. This stabilizes permanganate relative to a hypothetical all-sulfide analogue.

sulfide is larger, more polarizable and much easier to oxidize than oxide. An attempted Mn(VII) sulfide would therefore combine an exceptionally oxidizing metal center with reducing ligands: internal redox can reduce manganese while oxidizing sulfur, for example toward S–S-bonded or elemental sulfur products. The larger sulfur donors also provide less favorable short multiple bonding to the small, highly charged manganese center. The oxygen compound supports Mn(VII); the sulfide combination is redox-incompatible. This predicts instability without requiring a specific unprovided decomposition product.

An organic substance may also contain nitrogen, sulfur, phosphorus, halogens and, in some cases, metals or other elements. “Organic” does not mean “made of only carbon, hydrogen and oxygen”. Detection generally requires converting a covalently bound element into a species that an appropriate inorganic test can recognize.

A historically available general method is the sodium fusion test. Fusion converts suitable nitrogen-containing material into cyanide, sulfur into sulfide, and chlorine-, bromine- or iodine-containing material into the corresponding soluble halides. The cooled reaction material is worked up to an aqueous extract, with separate portions reserved for separate tests. The transformations are analytical conversion principles, not claims that every nitrogen or sulfur compound must give quantitative recovery under any fusion conditions. Blanks and a known positive material are essential when a negative result is to be interpreted.^[ref]

For nitrogen, a suitable cyanide-containing extract is treated with a fresh iron(II) reagent and then brought through the appropriate oxidation and acidification sequence to obtain Prussian blue. Formation of ferrocyanide is represented byThe eventual ferric ferrocyanide material provides the blue observation. It is not sufficient simply to add any iron salt and assume that a positive blue must appear. Another classical principle converts nitrogen in suitable organic materials into Ammonia by heating with alkaline reagents, then recognizes the ammonia in a receiver. That test has substrate-dependent limitations and is not a universal replacement for complete nitrogen analysis. A later specialized nitrogen-digestion protocol must not be silently attributed to 1865.

For sulfur, a sulfide-containing alkaline extract can give black lead sulfide with a suitably introduced lead reagent:The strongly acidic form of the reagent conditions changes the available sulfide, so conditions must be controlled. Oxidizing the material to sulfate and identifying a persistent barium sulfate precipitate supplies another principle, using sulfur-free reagents and excluding pre-existing sulfate contamination. If nitrogen and sulfur occur together, thiocyanate formation can alter a fusion test; failure of the expected cyanide reaction is not conclusive evidence that nitrogen is absent.

For chlorine, bromine and iodine, remove interfering cyanide and sulfide by an appropriate controlled treatment of a separate extract portion, then use silver nitrate under suitable nitric-acid conditions. The precipitates are ordinarily white silver chloride, cream silver bromide and yellow silver iodide. Their differing behaviour with aqueous Ammonia provides corroboration: chloride dissolves relatively readily, bromide requires stronger conditions, and iodide is resistant. Do not use hydrochloric acid to prepare the portion in which original chloride is being sought. Fluorine requires a different recognition method: soluble silver fluoride means this precipitation scheme does not provide an equivalent fluoride test.

For phosphorus, oxidize a suitable portion to phosphate, then apply a phosphate test such as yellow ammonium phosphomolybdate formation under the proper acidic conditions. Arsenic species and other interferences must be excluded when relevant. Mineral ash can reveal metal constituents through their specific precipitation or flame reactions, but oxidation during ashing can change their original chemical form. Absence of a visible ash does not prove absence of every metallic or otherwise volatile element.

A positive result identifies an element or an operationally generated ion; it does not establish which functional group contained it in the original molecule. Conversely, an incomplete conversion can give a false negative. This is why the three-element premise used in the preceding combustion calculation should be checked rather than accepted merely because a substance is described as organic.

A sulfide ion is formally ${\mathrm{S}}^{2-}$. Relative to oxide it is larger, more polarizable and more readily oxidized; the ability of a metal to support a high oxidation state need not survive replacement of oxygen by sulfur.