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Symmetric-function involution (ω(er​)=hr​,ω(pr​)=(−1)r−1pr​)

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2026-10-14  NaN By others on same topic  0 Discussions Create my own version
The Fundamental theorem of symmetric polynomials gives freely generated elementary functions, so sending each er​ to hr​ defines an algebra homomorphism. For E(t)=∑er​tr and H(t)=∑hr​tr, E(−t)H(t)=1. Applying the homomorphism shows ω(H(t))=E(t), hence ω2=1. Taking logarithms of H gives the displayed action on power sums. It preserves the Hall inner product of symmetric functions because each power-sum basis vector acquires only a sign.

 Incoming links (4)

  • Cauchy identity for symmetric functions
  • Dual Cauchy identity for symmetric functions
  • Past exam of the mathematics course of the University of Cambridge / 2001 / iii / Paper 77 / 4 / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2001 / iii / Paper 77 / 7 / b / Solution

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