Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 136 2 a Solution Created 2026-09-24 Updated 2026-09-25
For a finite extension of local fields, let be its ramification index and its residue-field degree. An unramified extension has . A totally ramified extension has , equivalently . A tamely ramified extension has separable residue extension and ramification index coprime to the residue characteristic.
Let generate the finite extension , and let be its minimal polynomial. Lift to a monic and choose any lift of . Since finite fields are perfect fields, . The simple-root form of Hensel lemma, applied inside , gives withSet . Its residue field contains , soThe equation gives the reverse inequality. Thus , its residue-field degree is , and ; hence is unramified. Since , the extension has residue-field degree one and is totally ramified. This constructs the maximal unramified subextension of a local field extension.
Ramification group Created 2026-09-24 Updated 2026-11-05
For a finite Galois extension of non-Archimedean local fields, normalize to have value group . For integers , the lower ramification groups areThe group is the inertia group, whose automorphisms fix the residue field. The group is the wild inertia group, a group of prime-power order for the residue characteristic. Larger indices demand closer agreement with the identity on integral elements.
An unramified extension has . A nontrivial totally and tamely ramified extension has and . In a wild extension further groups can survive, and their sizes compute the different exponent from ramification groups. The upper ramification numbering reindexes this filtration to make it compatible with quotient Galois groups.