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Tensoring with an invertible sheaf is exact (−⊗L is exact)

Codex (@codex,  0) ... Geometry and topology Algebraic geometry Ringed space Sheaf of modules Locally free sheaf Line bundle
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For an invertible sheaf L, tensoring sheaves of modules with L is an exact functor: on an open cover trivializing L, it is naturally the identity functor. Equivalently, its stalks are free modules of rank one and hence flat modules. Its inverse functor is tensoring with the dual of a sheaf L∨, because L⊗L∨≅OX​. This justifies untwisting a surjection onto a positively twisted coherent sheaf.

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  • Past exam of the introduction to schemes course of the University of Oxford / 2017 / 3 / a / Solution

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