Use an orthonormal real Fourier series basis on a circle of length , with . Retain the constant coefficient and the sine/cosine pair for each . The oscillator action becomes . A product of real Gaussian integrals gives the displayed functional determinant, with independent of . Ratios for two frequencies converge regardless of . The absolute limit requires its normalization: gives the thermal partition function of a quantum harmonic oscillator in the limit. Multiplying this choice by an oscillating positive sequence preserves all frequency ratios but destroys the absolute limit.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 304 1 i Solution Created 2026-10-03 Updated 2026-10-05
For , the quantum harmonic oscillator has energies , , in units . For positive inverse temperature , taking the trace in the energy basis and summing a geometric series givesThis is the thermal partition function of a quantum harmonic oscillator, including its zero-point energy. The assumptions ensure convergence; at the free particle on the noncompact line instead has an infinite spatial-volume factor.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 304 1 iv Solution Created 2026-10-03 Updated 2026-10-05
The frequency-independent measure factor cancels in the ratio:Upon analytic continuation in frequency, this has poles at and zeros at , for , apart from cancellations when numerator and denominator vanish together. They match those of . To justify equality, rather than merely matching this divisor, use the hyperbolic-sine infinite productIt follows from pairing the Weierstrass product for the reciprocal gamma function at opposite imaginary arguments and using the Gamma reflection formula. Normal convergence on compact sets follows from . Thus, for positive real frequencies,The cutoff ratio determines the frequency dependence, agreeing with the thermal partition function of a quantum harmonic oscillator.
The printed assertion about an absolute needs a normalization qualification: independence of from alone does not ensure existence of a nonzero limit. Set . Then , so if , its limit is . The choice gives the required limit. Conversely, is a positive frequency-independent normalization with no absolute limit, though every ratio above still converges. Matching zeros and poles alone also permits nonvanishing entire functions; the convergent normalized product is what rules them out here.