Uncountability obstruction to enumerating infinite Cartesian products ($\{0,1{\}}^{\mathbb{N}}\text{ is uncountable}$)

An infinite Cartesian product of finite sets need not admit any complete list enumeration. For the repeated binary factor, suppose the output lists all sequences as $z_0,z_1,\dots$. Define a sequence by $b_i=1-z_i(i)$. It is a valid binary sequence but differs from the $i$-th output at coordinate $i$, a contradiction. This is Cantor's diagonal argument. Consequently fair binary products can recursively enumerate the choices from finitely many possibly infinite lists, but cannot solve the unrestricted infinite-family specification. A finite-family algorithm's restriction must be explicit.