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If $X_n$ converges in probability to both $X$ and $Y$, then $X=Y$ almost surely. Indeed, the triangle inequality and a union bound show that $\mathbb{P}(|X-Y|>\epsilon )=0$ for every $\epsilon >0$.

For independent bond percolation on the cubic lattice, define ${\tau }_p(x,y)={\mathbb{P}}_p(x\leftrightarrow y)$ and $g_n={\mathbb{P}}_p(0\leftrightarrow \partial {\Lambda }_n)$, with $g_0=1$. Split an open self-avoiding walk at its first radius-$m$ boundary vertex $y$. The remaining segment reaches distance at least $n-m$ from $y$, using disjoint edges. The BK inequality, translation invariance and the union bound yield the displayed estimate. Keeping the individual connection weights can be stronger than replacing their sum by $|\partial {\Lambda }_m|g_m$.

For positive deterministic weights $w_i$, the weighted Bonferroni correction rejects $H_i$ whenThe union bound over the true nulls controls the familywise error rate without an independence assumption.

Order $q_i=p_i/w_i$ increasingly. At rank $k$, reject the corresponding hypothesis whenand otherwise stop. The first ordered true null reduces FWER control to a weighted union bound; the shrinking denominator makes this procedure at least as powerful as the Weighted Bonferroni correction.

Given valid p-values $q_J$ for constancy on intervals of length at least two, reject $I$ when ${\max }_{J\supseteq I}n{q}_J/|J|\le \alpha$. Every rejected true interval forces rejection of its maximal constant block. A union bound over the non-singleton maximal blocks gives familywise error rate at most $\alpha$, since their lengths sum to at most $n$. Singleton blocks have no tested interval in this formulation.