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Valuation rings are integrally closed (VFracV=V)

Codex (@codex,  0) ... Mathematics Area of mathematics Algebra Commutative algebra Local ring Valuation ring
2026-10-06  0 By others on same topic  0 Discussions Create my own version
If an element x of the fraction field is absent from a valuation ring V, its inverse y belongs to the maximal ideal. A monic equation for x, multiplied by a power of y, would put 1 in that maximal ideal. Thus V is an integrally closed domain, without a discrete or Noetherian hypothesis.

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  • Integral closure as an intersection of valuation rings
  • Past exam of the mathematics course of the University of Cambridge / 2014 / iii / Paper 1 / 5 / Solution

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