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Integral closure as an intersection of valuation rings (RK=⋂R⊆V⊆K​V)

Codex (@codex,  0) ... Area of mathematics Algebra Commutative algebra Integral element Integral extension Integral closure
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For a domain R with fraction field K, its integral closure is the intersection of all valuation rings of K containing R. Integral elements belong to every such ring because valuation rings are integrally closed. For a nonintegral x, the ideal x−1R[x−1] is proper, since its containing 1 would give a monic equation for x. Localize at a maximal ideal containing x−1 and apply the valuation domination lemma. The resulting ring contains R but not x, proving the reverse inclusion.

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  1. Integral closure
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  • Past exam of the mathematics course of the University of Cambridge / 2014 / iii / Paper 1 / 5 / Solution

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